Question

The kinetic energy of a body is increased by `21%`. What is the percentage increase in the magnitude of linear momentum of the body?

Answer 1

`E_(k_2)=121/100E_(k_1)` or `1/2mv_2^2=(121)/(100)1/2mv_1^2`
or `v_2=11/10v_1` or `mv_2=(11)/(10)1/2mv_1` or `p_2=11/10p_1`
or `p_2/p_1-1=11/10-1=1/10=0.1`
or `(p_2-p_1)/(p_1)xx100=1/10xx100=10`
So the percentage increase, in the magnitude of linear momentum is `10%`.