Question

An aeroplane takes off at an angle or `30^(@)` to the horizontal. If the component of its velocity along the horizontal is `240 km h^(-1)`. What is the actual velocity. ? Also find the vertical component of its velocity ?

Answer 1

Let (v) be the actual velocity of aroplane while taking off. As per question
` u cos 30^(@) =240`
or 1 u= (240)/( cos 30^(@) =9240)/(aqrt 3//2) =(480)/(sqrt 3) = (480 sqrt)/3`
`= 160 sqrt 3 km h^(-1)`
Vertical component velocity of aeroplace
` =u sin 30^(@) = 160 sqrt 3 xx 1//2`
`=80 sqrt 3 km h^(-1)`.