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The shear modulus for a metal is `50000 Mpa`. Suppose that a shear fore of `200 N` is applied ot the upper surface of a cube of this metal that is `3.0 cm` on each edge. How far will the top surface be displaced?

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Shearing strain`=/_L//L=(F/A)S`
`=2000/[L^(2)(5x10^(10))]=(4xx10^(-9))/L^(2)`
Solving for `/_L` with `L=0.030m`, we have
`/_L=1.33xx10^(-7)m=0.133mum`

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