Question

A `0.05 m` cube has its upper face displaced by `0.2 cm` by a tangential force of `8N`. Calculate the shearing strain, shearing stress and modulus of rigidity of the material of the cube.

Answer 1

`l=5xx10^(-2)m, /_l=0.2cm=0.2xx10^(-2)m, F=8N`
shearing strain `=(/_L)/l=0.2/5=0.04`
Shearing stress `=F/(lxxl)=8/((5xx10^(-2)))=3200Nm^(-2)`
Modulus of rigidity
`eta=("Shearing stress")/("Shearing strain") =3200/0.04=80000Nm^(-2)=8xx10^(4)Nm^(-2)`