Question

A hydraulic press contains `0.25 m^(3)(250L)` of oil. Find the decrease in volume of the oil wen it is subjected to a pressure increase `/_p=1.6xx10^(7)Pa`. The bulk modulus of the oil is `B=5.0xx10^(9)Pa`.

Answer 1

`B=-(/_p)/(/_V//V_0)=-((0.25m^(3))(1.6xx10^(7)Pa))/(5.0xx10^(9)Pa)`
`=-8.0xx10^(-4)m^(3)=-0.80L`
Even through the pressure increase is very large, the fractional change in volume is very small.
`:./_V//V_0=(-8.0xx10^(-4)m^(3))/(0.25m^(3))=-0.0032` or `-0.32%`