Correct Answer - A
`l_(1) +2l_(2) +l_(3) =` constant ltbrltgt `(dl_(1))/(dt) +2(dl_(2))/(dt) +(dl_(3))/(dt) = 0`
`(d^(2)l_(1))/(dt^(2)) +2(d^(2)l_(2))/(dt^(2)) +(d^(2)l_(3))/(dt^(2)) = 0`
`rArr -a +2a_(B) +f = 0`
`a_(B) =- (1)/(2) (f-a) rArr a_(B) = (1)/(2) (f-a) uarr`