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The breaking stress for a substance is `10^(6)N//m^(2)`. What length of the wire of this substance should be suspended verticaly so that the wire breaks under its own weight? (Given: density of material of the wire `=4xx10^(3)kg//m^(3)` and `g=10 ms^(-12))`
A. `10m`
B. `15m`
C. `25m`
D. `34m`

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Correct Answer - C
Breaking stress`=("Maximum weight")/("Area of cross section")`
`10^(6)=(alrhog)/a=lrhog`
or `l=(10^(6))/(rhog)=(10^(6))/(4xx10^(3)xx100m=25m`

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