Correct Answer - C
From the free body diagram of the elevator
`T-mg=ma`
`T=m(g+a)`
Stress is cable is `alpha=T/A=(m(g+a))/a`
From the given condition `alphalealpha_("max")/2`
`(m(g+a))/Alesigma_("max")/2`
`g+ale(2xx10^(9))/2xx(10^(-4))/(2xx10^3)=50`
`g+ale(2xx10^(9))/2xx(10^(-4))/(2xx10^(-3))=50`