Correct Answer - A::C
Area of cross section
`A=(pid^(2))/4`
where `d` is the diameter of the wire. Therefore
`l=(4FL)/(pid^(2)Y)`
since `F, L` and `Y` are the same for wires `A` and `B`
`:. Lprop1/(d^(2))`
i.e., the extension is inversely proportional to the square of the diameter. Hence choice a is correct.The strain is
`l/L=(4F)/(pid^(2)Y)`
Thus strain `prop1/(d^(2))`
i.e., the extension is inversely proportional material to the square of the diameter. Hence choice a is correct. The strain is
`l/L=(4F)/(pid^(2)Y)`
Thus, strain`prop1/(d^(2))`
Hence the correct choice are a and c.