Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
67 views
in Physics by (82.0k points)
closed by
A body starts from rest and moves with constant acceleration. The ratio of distance covered by the body in `nth` second to that covered in `n` second is.
A. `2/(n^(2))-1/n`
B. `2/(n^(2))+1/n`
C. `2/n-1/(n^(2))`
D. `2/n+1/(n^(2))`

1 Answer

0 votes
by (84.3k points)
selected by
 
Best answer
Correct Answer - C
distance covered `n^(th)` second is `(a)/(2)(2n-1)`
distance covered in n second `=1/2 an^(2)`
this implies ratio `=2/n-1/(n^(2))`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...