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For a particle moving in a straight line, the displacement of the particle at time `t` is given by
`S=t^(3)-6t^(2) +3t+7`
What is the velocity of the particle when its acceleration is zero?
A. `- 9 ms^(-1)`
B. `-12 ms^(-1)`
C. `3 ms^(-1)`
D. `42 ms^(-1)`

1 Answer

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Best answer
Correct Answer - A
`V=(ds)/(dt) =3t^(2)-12 t+3`
`a=(dv)/(dt) =6t-12=0`
t=2s
At t=2s,
`V =3xx2^(2)-12xx2+3=12-24+3=-9 m//s`

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