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A substance breaks down under a stress of `10^(5) Pa`. If the density of the wire is `2 xx 10^(3) kg//m^(3)`, find the minimum length of the wire which will break under its own weight `(g= 10 ms^(-12))`.

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Correct Answer - 5
`Mg=PA: A` is sectional area
`Alqg=10^(5)A`
`l=(10^(5))/(2xx10^(3)xx10)=5m`

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