Question

A uniform rod of length L and density `rho` is being pulled along a smooth floor with a horizontal acceleration `alpha` (see Fig.) The magnitude of the stress at the transverse cross-section through the mid-point of the rod is……..

Answer 1

Let `A` be area of cross section of the rod.
Mass `mxx"volume"xx"density =(L/2A)rho`
`T=-ma=(L/2Arhoa)`
Therefore stress `T/A=1/2rhoaL`