Question

A glass tube of uniform internal radius(r) has a valve separating the two identical ends. Intially, the valve is in a tightly closed position. End 1 has a hemispherical soap bubble or radius r. End 2 has sub-hemispherical soap bubble as shown in figure. Just after opening the valve,

A. Air from end `1` flows towards end `2`. There is no change in the volume of the soap bubble.
B. Air from end `1` flows towards end `2`. Volume of the soap bubble at end `1` decreases.
C. No change occurs.
D. Air from end `2` flows towards end `1`. Volume of the soap bubble at end `1` increases.

Answer 1

Correct Answer - B
`/_p_(1)=(4T)/(r_(1))` and `/_p_(2)=(4T)/(r_(2))`
`r_(1)ltr_(2):./_p_(1)gt/_p_(2)`
Therefore air will flow from `1` to `2` and volume of bubble at end `1` will increase.