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Acceleration versus velocity graph of a aprticle moving in a straight line starting form rest is as shon in figure. The corresponding velocity-time graph would be
image
A. image
B. image
C. image
D. image

1 Answer

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Correct Answer - D
`a=-kv+c [k gt 0, c gt 0]`
`int (dv)/(-kv+c)=intdtrArr-1/k ln(-kv+c)=t`
`rArr kv=c-e^(-kt)`

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