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The trajectory of a projectile in a vertical plane is `y=sqrt(3)x-2x^(2)`. `[g=10 m//s^(2)]`
image
Time of flight of the projectile is :-
A. `sqrt(3/10)s`
B. `sqrt(10/3)s`
C. `1s`
D. `2s`

1 Answer

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Best answer
Correct Answer - A
Time of fight `=(2u sin theta)/g=(2xxsqrt(10)xxsqrt(3)/2)/10=sqrt(3)/10`

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