The maximum distance covered by the vehicle before coming to rest `=(v^(2))/(2a)=((15)^(2))/(2(0.3))=375m`
The corresponding time `(t)=(v)/(a)=(15)/(0.3)=50s`. Therefore after `50 seconds`, the distance covered by the vehicle `=375m` from the instant of application of the brakes.
`rArr` The distance of the vehicle from the traffic light after one minute `=(400-375)m=25m`