# The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta). This equation can be used for calculating various pheno

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The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta). This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing.
From a certain tower of unknown height it is found that the maximum range at a certain projection velocity is obtained for a projection angle of 30^(@) and this range is 10sqrt(3)m. The projection velocity must be
A. 10m//s
B. 10sqrt(3)m//s
C. (10)/(sqrt(3))m//s
D. 5m//s

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tan theta=(u^(2))/(Rg) rArr u=sqrt(Rg tan theta)=10m//s