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Calculate the mass of urea (NH2CONH2) required in making 2.5 kg of 0.25 molal aqueous solution. 

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Molar mass of urea (NH2CONH2) = 2(1 × 14 + 2 × 1) + 1 × 12 + 1 × 16 = 60 g mol−1 

0.25 molar aqueous solution of urea means:

 1000 g of water contains 0.25 mol = (0.25 × 60)g of urea

 = 15 g of urea

 That is, (1000 + 15) g of solution contains 15 g of urea

 Therefore, 2.5 kg (2500 g) of solution contains = 36.95 g

= 37 g of urea (approximately) 

Hence, mass of urea required = 37 g

 Note: There is a slight variation in this answer and the one given in the NC

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