Fewpal
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Answer: Given

Mass % of iron = 69.9 % 

Mass % of oxygen = 30.1 % 

Element

Atomic mass

Mass %

Mass % / atomic mass

Fe

55.85

69.9

69.9/55.85 = 1.25

O

16.00

30.1

30.1/16.00 = 1.88

Fe : O = 1.25 : 1.88

Converting in simple ratio we get

Fe : O = 2 : 3

Hence, the empirical formula of the iron oxide is Fe2O3.

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