# Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution.

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Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1.

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Given that

0.375 Molar aqueous solution

Molar represent molarity of the solution

Hence given molarity of solution will 0.375M

Formula of molarity

Molarity (M) = No. of moles of solute / volume of solution in liter

Volume in liter = 500 ml = 0.5 liter (1000 ml = 1 liter)

Putting the values in above formula we get

Number of moles = 0.375 × 0.5 = 0.1875 mol

Use formula

Number of moles = mass / molar mass

Molar mass of sodium acetate (CH3COONa) = 82.0245 g mole-1 (Given)

Putting the above values in formula we get

Mass of sodium acetate (CH3COONa) = (82.0245 g mol-1) (0.1875 mole) = 15.38 g