Here, `h=20m, g=10 m//s^(2), u=upsilon_(0)`
Initial energy `=mgh+(1)/(2)m upsilon_(0)^(2)`
final energy `=mgh(` As ball rebounds to the same height `)`
According to question
`(1)/(2)((1)/(2)m upsilon_(0)^(2)+mgh)=mgh`
`(1)/(2)m ((1)/(2)upsilon_(0)^(2)+gh)=mgh` or ` (1)/(4)upsilon_(0)^(2)+(1)/(2)gh=gh`
or `(1)/(4)upsilon_(0)^(2)=(1)/(2)gh ` or ` upsilon_(0)^(2)=2gh`
`upsilon_(0)=sqrt(2gh)=sqrt(2xx10xx20)=20m//s`