The retardation due to friction is,

`a=("force of friction")/("mass")=(mu mg)/(m)=-mug`

Further,`" " v_(0)`=at

Therefore, `" "t=(v_(0))/(a)=(v_(0))/(mug)`………..(i)

From work energy theorem,

work done by force of friction =change in kinetic energy

or `" " W=(1)/(2)mv_(0)^(2)`..............(ii)

Mean power`=(W)/(t)`

From Eqs. (i) and (ii), we get

`P_(mean)=(1)/(2) mu mgv_(0)`

Substituting the values, we have

`P_(mean)=(1)/(2)xx0.27xx1.0xx9.8xx1.5~~2 W`