Question

Calculate the angular acceleration produced in a grind stone of moment of inertia `3 kg m^(2)` under the action of a torque of `3 pi N -m`.

Answer 1

Here, `alpha = ? I = 3 kg m^(2), tau = 3 pi N -m`, From `tau = I alpha, alpha = (tau)/(I) = (3pi)/(3) = pi rad//s^(2)`.