Correct Answer - A
Here, `R = 0.5m, M =0.45 kg`
`m = 0.05 kg, t = 0.25 m`
`upsilon = 9 m//s, omega = ?`
As is clear from Fig.
Angular momentum
`I omega = 2 m upsilon xx r`
`((1)/(2)MR^(2)) omega = 2m upsilon xx r`
`omega = (4m upsilon xx r)/(MR^(2))`
`omega = (4 xx 0.05 xx 9 xx 0.25)/(0.45 xx (0.5)^(2)) = 4 rad//sec`