Question

Water is flowing in a river at `2 ms^(-1)`. The river is `50 m` wide and has an average depth of `5 m`. The power available from the current in the river is (Density of water `= 1000 kg m^(3)`
A. `0.5 MW`
B. `1 MW`
C. `1.5 MW`
D. `2 MW`

Answer 1

`Power = Kinetic energy of water flowing per second `= (1)/(2) xx area of cross - section xx density xx (velocity)^(3)`
`= (1)/(2) xx 50 xx 5 xx 1000 xx 2^(3)W = 10^(6)W = 1MW`