Question

To What depth must a rubber ball be taken in deep sea so that its volume is decreased y 0.1 %. (The bulk modulus of rubber is `9.8 xx 10^8 Nm^(-2)` , and the density of seac water is `10^3 kg m^(-3).)`

Answer 1

Given, `(Delta V)/(V) = (0.1)/(100) , B = 9.8 xx 10^8 N//m^2 , rho = 10^3 kg//m^3`
Let h be the depth of water at which the rubber ball be taken, then increases in pressure `P = h rho g`
`B = (P)/(Delta V//V) = (h rho g)/(Delta V//V)` or `h = B(Delta V//V)/(rhog) = ((9.8 xx 10^8) xx(0.1//100))/(10^3 xx 9.8) = 100m`