Heat lost by water to come from `15^@C` to `0^@C is H_1 = (40)/(1000) xx(4.2xx 10^3) xx(15 - 0) = 2520 J` Heat required to convert 10 g ice into 10 g water at `0^@C is H_2 = (10)/(1000) xx (3.36 xx 10^5) = 3360 J` Since `H_2 gt H_1` so the whole ice will not be converted into water, whereas the temperature of the whole water will be `0^@C.` Therefore the temperature of the mixture is `0^@C.`