# In car lift compressed air exerts a force F_1 on a small piston having a radius of 5 cm. This pressure is transmitted to a second piston of radius 1

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In car lift compressed air exerts a force F_1 on a small piston having a radius of 5 cm. This pressure is transmitted to a second piston of radius 15 cm. If the mass of the car to be lifted is 1350 kg, what is F_1 ? What is the pressure necessary to ac complish this task ?

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Correct Answer - 1.47 xx 10^3 N; 1.87 xx 10^5 Pa
F_1 = (F_2)/(A_2)xxA_1 = ((1350 xx 9.80)xxpi(5xx5))/(pi (15xx15))
= 1.47 xx 10^3 N The air pressure that will proudce this force is P =(F_1)/(A_1) = (1.47xx10^3)/((22//7) (5xx 10^(-2))^2)
 =1.87 xx 10^5 Pa