Question

In car lift compressed air exerts a force `F_1` on a small piston having a radius of 5 cm. This pressure is transmitted to a second piston of radius 15 cm. If the mass of the car to be lifted is 1350 kg, what is `F_1 ?` What is the pressure necessary to ac complish this task ?

Answer 1

Correct Answer - `1.47 xx 10^3 N; 1.87 xx 10^5 Pa`
`F_1 = (F_2)/(A_2)xxA_1 = ((1350 xx 9.80)xxpi(5xx5))/(pi (15xx15))`
`= 1.47 xx 10^3 N` The air pressure that will proudce this force is `P =(F_1)/(A_1) = (1.47xx10^3)/((22//7) (5xx 10^(-2))^2)`
` =1.87 xx 10^5 Pa`