Correct Answer - [`1//2`]
Let `rho` the density of liquid. Then
`F_(1)=(delta P)A=rho gh A`
In the second case, `F_(2)=`rate of change of momentum
`=` mass of water striking per sec x velocity
`=(A v xx rho)xx v= A rho v^(2) =A rho (sqrt(2 gh))^(2)`
`=A rho xx2 gh`
`:. (F_(1))/(F_(2))=(1)/(2)`