Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
254 views
in Physics by (76.3k points)
closed by
A particle is projected upwards with velocity `40 m//s.` Taking the value of `g=10 m//s^2` and upward direction as positive, plot a-t,v-t and s-t graphs of the particle from the starting point till it further strikes the ground.

1 Answer

0 votes
by (76.6k points)
selected by
 
Best answer
image
The particle reaches the highest point after time t.
`0=40-g timpliest=4 s`
The particle returns to the point of projection at time `t=8s`.
v-t graph: `t=0, v=40 m//s`
`t=4 s, v=0`
`t=8 s, v=-40 m//s`
`v=u-g t=40-10 t`
Shape: `y=40-10x`(straght line)
`y=c+mx`
`c=40`, +ve
`m=-10`, -ve
image
s-t graph: Maximum height attained by the particle
`0=(40)^(2)-2gh=1600-2xx10xxh`
`implies h=80 m`
`t=0, s=0`
`t=4 s, s=80 m`
`t=8 s, s=0`
`s=ut-1/2 g t^(2)`
`s=40 t-5t^(2)`
Shape: `y=40x-5x^(2)` (parabola)
Since the coefficient of `x^(2)` is -ve, the parabola is open downward.
image
a-t graph: `a=-g=-10 m//s^(2)`
Shape: `y=-10` (straight line, parallel to the x-axis, below the origin)
image
Note: Upward direction is assumed positive.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...