Question

A particle moves in a straight line such that the displacement x at any time t is given by `x=6t^(2)-t^(3)-3t-4`. X is in m and t is in second calculate the maximum velocity (in `ms^(-1))` of the particle.

Answer 1

Correct Answer - 9
`x=6t^(2)-t^(3)-3t-4v=12t-3t^(2)-3`
`V="max when" (dv)/(dt)=0impliest=2sec`
`:. v(2)=9ms^(-1)`