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An astronomical telescope has a magnifying power of `10`. In normal adjustment, distance between the objective and eye piece is `22 cm` calculate focal length of objective lens.

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Here, `m = -10, L = 22 cm., f_0 = ?`
As `m = - (f_0)/(f_e) :. -10 = -(f_0)/(f_e)` or `f_0 = 10 f_e`
As `L = f_0 + f_e`
`:. 22 = 10 f_e + f_e = 11 f_e`
or `f_e = (22)/(11) = 2 cm`
`f_0 = 10 f_e = 10 xx 2 = 20 cm`.

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