Here, combined focal length of glass lens and liquid lens, `F = a`, and Focal length of convex lens, `f_1 = b` If `f_2` is focal length of liquid lens, then
`(1)/(f_1)+(1)/(f_2)=(1)/(F)`
`(1)/(f_2)=(1)/(F)-(1)/(f_1) = ((1)/(a) - (1)/(b))`
The liquid lens is plano concave lens for which `R_1 = -r, R_2 = oo`
From `(1)/(f_2)=(mu -1) ((1)/(R_1) - (1)/(R_2))`
`((1)/(a) - (1)/(b)) = (mu - 1) ((1)/(-r) - (1)/(- oo))`
`:. (mu - 1) = (r)/(b) - (r)/(a)`
`mu = 1 + (r)/(b) - (r)/(a)`.