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0 votes
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in Physics by (76.5k points)
A stone projected vertically up from the ground reaches a height `y` in its path at `t_(1)` seconds and after further `t_(2)` seconds reaches the ground. The height `y` is equal to
A. `(1)/(2) g (t_(1) + t_(2))`
B. `(1)/(2)g (t_(1) + t_(2))^(2)`
C. `(1)/(2) g t_(1) t_(2)`
D. `g t_(1) t_(2)`

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1 Answer

0 votes
by (76.7k points)
Correct Answer - C
`h = y = (1)/(2) g t_(1) t_(2)`

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