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Calculate the refractive index of the material of an equilaterial prism for which angle of minimum deviation is `60^@`.

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Correct Answer - `sqrt(3)`
Here, `A = 60^@, delta_m = 60^@, mu = ?`
`mu = (sin(A + delta_m)//2)/(sin A//2) = (sin(60^@ + 60^@)//2)/(sin 60^@//2)`
=`(sin 60^@)/(sin 30^@) = (sqrt(3)//2)/(1//2) = sqrt(3)`.

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