# The displacement of a particle moving in straight line is given as function of time as s = ((t^(3))/(3) - (3t^(2))/(2) + 2t), s is in m and t is in

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The displacement of a particle moving in straight line is given as function of time as s = ((t^(3))/(3) - (3t^(2))/(2) + 2t), s is in m and t is in sec. The particle comes to momentary rest n times Find the value of n

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s = (t^(3))/(3) - (3t^(2))/(2) + 2t
:. V = (ds)/(dt) = t^(2) - 3 t + 2
Since the particle comes to rest, therefore,
t^(2) - 3 t + 2 = 0
(t - 1) (t - 2) = 0
 t = 1 s " and " 2s
Hence, the particle comes to rest twice.
:. n = 2