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A ray of light suffers minimum deviation, while passing through a prism of refractive index `1.5` and refracting angle `60^@`. Calculate the angle of deviation and angle in incidence.

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Correct Answer - `37.2^@, 48.6^@`
`mu = 1.5, A = 60^@, delta_m = ?, i = ?`
As `(sin(A + delta_m)//2)/(sin A//2) = mu`
`:. (sin(60^@ + delta_m)//2)/(sin 60^@//2) = 1.5`
`sin(60^@ + delta_m)//2 = 1.5 sin 30^@ = 0.75`
`(60^@ + delta_m)/(2) = sin^-1 (0.75) = 48.6^@`
`delta_m = 2 xx 48.6 - 60^@ = 37.2^@`
`i = (A + delta_m)/(2) = (60^@ + 37.2)/(2) = 48.6^@`.

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