Steps of construction:
i) Draw line BC = 6 cm and an angle CBX = 60o. Cut off AB = 3.5. Join AC, triangle ABC is the required triangle.
ii) Draw perpendicular bisector of BC and bisector of angle B
iii) Bisector of angle B meets bisector of BC at P.
⟹ BP is the required length, where, PB = 3.5 cm
iv) P is the point which is equidistant from BA and BC, also equidistant from B and C.
PB = 3.6 cm