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The minimum magnifying power of an astronomical telescope is M. If the focal length of its eye-lens is halved, the minimum magnifying power will become:
A. M/2
B. 2M
C. 3M
D. 4M

1 Answer

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Best answer
Correct Answer - B
`MP=-((f_(0))/(f_(theta)))`
If we use a eyepiece of focal length halved, then MP become double.

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