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The half-life of a radioactive substance is 3h and its activity is `1mu Ci`. Then the activity after 9h will be (in `mu Ci`)-
A. `1/9`
B. `1/27`
C. `1/3`
D. `1/8`

1 Answer

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Best answer
Correct Answer - D
`A=A_(0)e^(-lambdat)`
`lambda=(ln2)/(t_(1//2)) t=9h` then `A=(A_(0))/8`

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