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0 votes
4.1k views
in Mathematics by (33.0k points)

The sum of first 40 positive integers divisible by 6 is 

(a) 2460 (b) 3640 (c) 4920 (d) 4860

1 Answer

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by (60.2k points)
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Best answer

The positive integers divisible by 6 are 6, 12, 18,....

Thus, the required sum is 4920.

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