HELLO,
Let the constant acceleratin be \(a\)
According to the question we have:
\(S_1=\frac{1}{2}a(p-1)^2\) --------- (1)
\(S_2=\frac{1}{2}a(p)^2\) ---------- (2)
Displacement in \((p^2-p+1)_{th} \) sec (\(S_0\)) = Dislacement in first \((p^2-p+1)\) sec - Displacement in first \((p^2-p)
\) sec
\(S_0=\frac{1}{2}a(p^2-p+1)^2-\frac{1}{2}a(p^2-p)^2\)
\(S_0=\frac{1}{2}a[(p^4+p^2+1-2p^3+2p^2-2p)-(p^4+p^2-2p^3)]\)
\(S_0=\frac{1}{2}a[1+2p^2-2p]\)
\(S_0=\frac{1}{2}a[1+p^2+p^2-2p]\)
\(S_0=\frac{1}{2}a[(p^2+1-2p)+(p^2)]\)
\(S_0=\frac{1}{2}a(p-1)^2+\frac{1}{2}a(p)^2\)
from equation (1) and (2) we get;
\(S_0=S_1+S_2\)
Hence, the correct option is (1)
I HOPE YOU WILL UNDERSTAND.