Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
61 views
in Physics by (41.2k points)
closed by
In an experiment four quantities a,b,c and d are measure with percentage error `1% , 2% , 3%`,and `4%` respectively quantity is P is calculate as follow
`P = (a^(3)b^(2))/(cd) %` error in `P` is
A. 0.14
B. 0.1
C. 0.07
D. 0.04

1 Answer

0 votes
by (57.1k points)
selected by
 
Best answer
Correct Answer - A
Here, `P=(a^(3)b^(2))/(cd)`
`therefore(DeltaP)/(P)xx100=((3Deltaa)/(a)+(2Deltab)/(b)+(Deltac)/(c)+(Deltad)/(d))xx100`
`" "=3(Deltaa)/(a)xx100+2(Deltab)/(b)xx100+(Deltac)/(c)xx100+(Deltad)/(d)xx100`
`" "=3xx1+2xx2+3+4`
`" "=3+4+3+4=14%`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...