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A cylindrical tube of uniform cross-sectional area A is fitted with two air tight frictionless postion.
image The pistons are connected to each other by a metallic wirte. Initially the pressure of the gas is `p_(o)` and temperature is `T_(o),` atmospheric pressure is also `p_(o)` Now the temperature of the gas is increased to `2T_(0),` the tension in the wire will be
A. `2p_(o)A`
B. `p_(o)A`
C. `(p_(o)A)/2`
D. `p_(o)A`

1 Answer

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Best answer
Correct Answer - B
Volume of the gas is constant
V= constant
image
`therefore propTi.e.,` Pressure will be doubled, temperature is doubled
`therefore" "p=2p_(o)`
Now let F be the tension in the wire. Then equilibrium of any one piston gives.
`F=(p-p_(o))A=(2p_(o)-p_(o))A=p_(o)A`

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