Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
146 views
in Physics by (90.2k points)
closed by
A body at a temperature of `727^(@)C` and having surface area `5 cm^(2)`, radiations `300 J` of energy each minute. The emissivity is(Given Boltzmann constant `=5.67xx10^(-8) Wm^(-2)K^(-4)`
A. `e=0.18`
B. `e=0.05`
C. `e=0.2`
D. `e=0.15`

1 Answer

0 votes
by (90.9k points)
selected by
 
Best answer
(a) `Q=Eat=esigma(T^(4)-T_(0)^(4))At`
Where `t=` time
`T_(0)=` temperature of surrounding when `TgtT_(0)`
`Q=e sigmaT^(4)At`
`300=exx(5.67xx10^(-8))(1000)^(4)(5.00xx10^(-4))(60)`
`e=0.18`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...