Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.3k views
in Physics by (90.2k points)
closed by
image
A tangential force `F` acts at the top of a thin spherical shell of mass `m` and radius `R`. Find the acceleration of the shell if it rolls without slipping.

1 Answer

0 votes
by (90.9k points)
selected by
 
Best answer
Let `f` be the force of friction between the shell and the horizontal surface
image
For translational motion
`F + f = ma` ….(i)
For rotational motion,
`FR-fR=Ialpha=I(a)/(R) (because a =R alpha "for pure rolling")`
`rArr F-f=I(a)/(R^(2))`...(ii)
Adding Eqs. (i) and (ii)
`2F=(m+(I)/(R^(2)))a=(m+(2)/(3)m)a=(5)/(3)ma`
or `F=(5)/(6)ma" "[because I_("shell")=(2)/(3)mR^(2)]`
`rArr a=(6F)/(5m)`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...