Question

When 400 J of heat are added to a 0.1 kg sample of metal, its temperature increase by `20(@)`C. What isthe specific heat of the metal?

Answer 1

Given, Heat `DeltaQ` = 400 J, Mass m = 0.1kg
Temperature `DeltaT` = `20^(@)C`
`therefore` Specific heat, `c=1/m.(DeltaQ)/(DeltaT) = (1/0.1)(400/3)= 200 Jkg^(-1)^(@)C^(-1)`