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Three rods of same cross-section but different length and conductivity are joined in series . If the temperature of the two extreme ends are `T_(1) and T_(2) (T_(1)gtT_(2))` find the rate of heat transfer H.
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Total thermal resistance
`R= R_(1) + R_(2) + R_93) = (L_(1)/K_(1)A) + L_(2)/(K_(2)A) + L_(3)/(K_(3)A)`
Now, Heat transfer `H=(T_(1)-T_(2))/R`
`therefore` `H = (T_(1)-T_(2))/(L_(1)/(K_(1)A) + L_(2)/(K_(2)A) + L_(3)/(K_(3)A))`

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